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4X^2-16X-54-1-4=0
We add all the numbers together, and all the variables
4X^2-16X-59=0
a = 4; b = -16; c = -59;
Δ = b2-4ac
Δ = -162-4·4·(-59)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20\sqrt{3}}{2*4}=\frac{16-20\sqrt{3}}{8} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20\sqrt{3}}{2*4}=\frac{16+20\sqrt{3}}{8} $
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